Solve sqrt{2}*sqrt{8}+sqrt[3]{-27}

$$\sqrt { 2 } \times \sqrt { 8 } + \sqrt[ 3 ] { - 27 }$$

Evaluate

$$1$$

Solution Steps

Factor 8=2\times 4. Rewrite the square root of the product \sqrt{2\times 4} as the product of square roots \sqrt{2}\sqrt{4}.

$$\sqrt{2}\sqrt{2}\sqrt{4}+\sqrt[3]{-27}$$

Multiply \sqrt{2} and \sqrt{2} to get 2.

$$2\sqrt{4}+\sqrt[3]{-27}$$

Calculate the square root of 4 and get 2.

$$2\times 2+\sqrt[3]{-27}$$

Multiply 2 and 2 to get 4.

$$4+\sqrt[3]{-27}$$

Calculate \sqrt[3]{-27} and get -3.

$$4-3$$

Subtract 3 from 4 to get 1.

$$1$$

Factor

$$1$$