Solve for x
x=\frac{y-\sqrt{2}}{3}
Solve for y
y=3x+\sqrt{2}
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3x=y-\sqrt{2}
Subtract \sqrt{2} from both sides.
\frac{3x}{3}=\frac{y-\sqrt{2}}{3}
Divide both sides by 3.
x=\frac{y-\sqrt{2}}{3}
Dividing by 3 undoes the multiplication by 3.
y=\sqrt{2}+3x
Swap sides so that all variable terms are on the left hand side.
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