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\sqrt{2}+2x=3\sqrt{2}
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
2x=3\sqrt{2}-\sqrt{2}
Subtract \sqrt{2} from both sides.
2x=2\sqrt{2}
Combine 3\sqrt{2} and -\sqrt{2} to get 2\sqrt{2}.
x=\sqrt{2}
Cancel out 2 on both sides.