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\sqrt{2}+\sqrt{3}\sqrt{3}\sqrt{2}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
\sqrt{2}+3\sqrt{2}
Multiply \sqrt{3} and \sqrt{3} to get 3.
4\sqrt{2}
Combine \sqrt{2} and 3\sqrt{2} to get 4\sqrt{2}.