Solve sqrt{2}+frac{sqrt{3}}{3}

$$\sqrt { 2 } + \frac { \sqrt { 3 } } { 3 }$$

Evaluate

$$\frac{\sqrt{3}\left(\sqrt{6}+1\right)}{3}\approx 1.991563832$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply \sqrt{2} times \frac{3}{3}.

$$\frac{3\sqrt{2}}{3}+\frac{\sqrt{3}}{3}$$

Since \frac{3\sqrt{2}}{3} and \frac{\sqrt{3}}{3} have the same denominator, add them by adding their numerators.

$$\frac{3\sqrt{2}+\sqrt{3}}{3}$$

Factor

$$\frac{\sqrt{3} {(\sqrt{2} \sqrt{3} + 1)}}{3} = 1.9915638315627209$$