Solve sqrt{2^2+9^2+15}+sqrt{25}-sqrt{36}=

$$\sqrt { 2 ^ { 2 } + 9 ^ { 2 } + 15 } + \sqrt { 25 } - \sqrt { 36 } =$$

Evaluate

$$9$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{4+9^{2}+15}+\sqrt{25}-\sqrt{36}$$

Calculate 9 to the power of 2 and get 81.

$$\sqrt{4+81+15}+\sqrt{25}-\sqrt{36}$$

Add 4 and 81 to get 85.

$$\sqrt{85+15}+\sqrt{25}-\sqrt{36}$$

Add 85 and 15 to get 100.

$$\sqrt{100}+\sqrt{25}-\sqrt{36}$$

Calculate the square root of 100 and get 10.

$$10+\sqrt{25}-\sqrt{36}$$

Calculate the square root of 25 and get 5.

$$10+5-\sqrt{36}$$

Add 10 and 5 to get 15.

$$15-\sqrt{36}$$

Calculate the square root of 36 and get 6.

$$15-6$$

Subtract 6 from 15 to get 9.

$$9$$

Factor

$$3^{2}$$