Solve sqrt{2^-6+16^-2}

$$\sqrt { 2 ^ { - 6 } + 16 ^ { - 2 } }$$

Evaluate

$$\frac{\sqrt{5}}{16}\approx 0.139754249$$

Solution Steps

Calculate 2 to the power of -6 and get \frac{1}{64}.

$$\sqrt{\frac{1}{64}+16^{-2}}$$

Calculate 16 to the power of -2 and get \frac{1}{256}.

$$\sqrt{\frac{1}{64}+\frac{1}{256}}$$

Add \frac{1}{64} and \frac{1}{256} to get \frac{5}{256}.

$$\sqrt{\frac{5}{256}}$$

Rewrite the square root of the division \sqrt{\frac{5}{256}} as the division of square roots \frac{\sqrt{5}}{\sqrt{256}}.

$$\frac{\sqrt{5}}{\sqrt{256}}$$

Calculate the square root of 256 and get 16.

$$\frac{\sqrt{5}}{16}$$