Solve sqrt{196}div13^1+sqrt{4}div2

$$\sqrt { 196 } \div 13 ^ { 1 } + \sqrt { 4 } \div 2$$

Evaluate

$$\frac{27}{13}\approx 2.076923077$$

Solution Steps

Calculate the square root of 196 and get 14.

$$\frac{14}{13^{1}}+\frac{\sqrt{4}}{2}$$

Calculate 13 to the power of 1 and get 13.

$$\frac{14}{13}+\frac{\sqrt{4}}{2}$$

Calculate the square root of 4 and get 2.

$$\frac{14}{13}+\frac{2}{2}$$

Divide 2 by 2 to get 1.

$$\frac{14}{13}+1$$

Convert 1 to fraction \frac{13}{13}.

$$\frac{14}{13}+\frac{13}{13}$$

Since \frac{14}{13} and \frac{13}{13} have the same denominator, add them by adding their numerators.

$$\frac{14+13}{13}$$

Add 14 and 13 to get 27.

$$\frac{27}{13}$$

Factor

$$\frac{3 ^ {3}}{13} = 2\frac{1}{13} = 2.076923076923077$$