Solve sqrt{192}+sqrt{27}

$$\sqrt { 192 } + \sqrt { 27 }$$

Evaluate

$$11\sqrt{3}\approx 19.052558883$$

Solution Steps

Factor 192=8^{2}\times 3. Rewrite the square root of the product \sqrt{8^{2}\times 3} as the product of square roots \sqrt{8^{2}}\sqrt{3}. Take the square root of 8^{2}.

$$8\sqrt{3}+\sqrt{27}$$

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$8\sqrt{3}+3\sqrt{3}$$

Combine 8\sqrt{3} and 3\sqrt{3} to get 11\sqrt{3}.

$$11\sqrt{3}$$