Solve for x
x=3\left(\sqrt{2}-20\right)\approx -55.757359313
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3\sqrt{2}-x=60
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
-x=60-3\sqrt{2}
Subtract 3\sqrt{2} from both sides.
\frac{-x}{-1}=\frac{60-3\sqrt{2}}{-1}
Divide both sides by -1.
x=\frac{60-3\sqrt{2}}{-1}
Dividing by -1 undoes the multiplication by -1.
x=3\sqrt{2}-60
Divide 60-3\sqrt{2} by -1.
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