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\frac{\sqrt{17}\left(\sqrt{17}\right)^{5}}{\left(\sqrt{17}\right)^{4}}
Divide \sqrt{17} by \frac{1}{\left(\sqrt{17}\right)^{5}} by multiplying \sqrt{17} by the reciprocal of \frac{1}{\left(\sqrt{17}\right)^{5}}.
\frac{\left(\sqrt{17}\right)^{6}}{\left(\sqrt{17}\right)^{4}}
To multiply powers of the same base, add their exponents. Add 1 and 5 to get 6.
\left(\sqrt{17}\right)^{2}
Cancel out \left(\sqrt{17}\right)^{4} in both numerator and denominator.
17
The square of \sqrt{17} is 17.