Solve sqrt{16}+3-27+sqrt{9}-sqrt{(-3)^2}

$$\sqrt { 16 } + 3 - 27 + \sqrt { 9 } - \sqrt { ( - 3 ) ^ { 2 } }$$

Evaluate

$$-20$$

Solution Steps

Calculate the square root of 16 and get 4.

$$4+3-27+\sqrt{9}-\sqrt{\left(-3\right)^{2}}$$

Add 4 and 3 to get 7.

$$7-27+\sqrt{9}-\sqrt{\left(-3\right)^{2}}$$

Subtract 27 from 7 to get -20.

$$-20+\sqrt{9}-\sqrt{\left(-3\right)^{2}}$$

Calculate the square root of 9 and get 3.

$$-20+3-\sqrt{\left(-3\right)^{2}}$$

Add -20 and 3 to get -17.

$$-17-\sqrt{\left(-3\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$-17-\sqrt{9}$$

Calculate the square root of 9 and get 3.

$$-17-3$$

Subtract 3 from -17 to get -20.

$$-20$$

Factor

$$-20$$