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4+|8-11|-\frac{45}{5}
Calculate the square root of 16 and get 4.
4+|-3|-\frac{45}{5}
Subtract 11 from 8 to get -3.
4+3-\frac{45}{5}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.
7-\frac{45}{5}
Add 4 and 3 to get 7.
7-9
Divide 45 by 5 to get 9.
-2
Subtract 9 from 7 to get -2.