Evaluate
11\sqrt{35}\approx 65.076877614
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2\sqrt{35}+9\sqrt{35}
Factor 140=2^{2}\times 35. Rewrite the square root of the product \sqrt{2^{2}\times 35} as the product of square roots \sqrt{2^{2}}\sqrt{35}. Take the square root of 2^{2}.
11\sqrt{35}
Combine 2\sqrt{35} and 9\sqrt{35} to get 11\sqrt{35}.
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