Solve sqrt{121}*sqrt{49}+(-6)^2+sqrt[4]{16}

$$\sqrt { 121 } \cdot \sqrt { 49 } + ( - 6 ) ^ { 2 } + \sqrt[ 4 ] { 16 }$$

Evaluate

$$115$$

Solution Steps

Calculate the square root of 121 and get 11.

$$11\sqrt{49}+\left(-6\right)^{2}+\sqrt[4]{16}$$

Calculate the square root of 49 and get 7.

$$11\times 7+\left(-6\right)^{2}+\sqrt[4]{16}$$

Multiply 11 and 7 to get 77.

$$77+\left(-6\right)^{2}+\sqrt[4]{16}$$

Calculate -6 to the power of 2 and get 36.

$$77+36+\sqrt[4]{16}$$

Add 77 and 36 to get 113.

$$113+\sqrt[4]{16}$$

Calculate \sqrt[4]{16} and get 2.

$$113+2$$

Add 113 and 2 to get 115.

$$115$$

Factor

$$5\times 23$$