Solve sqrt{100}-(sqrt{(-6)^2}divsqrt[3]{8})+sqrt[3]{-64}=

$$\sqrt { 100 } - ( \sqrt { ( - 6 ) ^ { 2 } } \div \sqrt[ 3 ] { 8 } ) + \sqrt[ 3 ] { - 64 } =$$

Evaluate

$$3$$

Solution Steps

Calculate the square root of 100 and get 10.

$$10-\frac{\sqrt{\left(-6\right)^{2}}}{\sqrt[3]{8}}+\sqrt[3]{-64}$$

Calculate -6 to the power of 2 and get 36.

$$10-\frac{\sqrt{36}}{\sqrt[3]{8}}+\sqrt[3]{-64}$$

Calculate the square root of 36 and get 6.

$$10-\frac{6}{\sqrt[3]{8}}+\sqrt[3]{-64}$$

Calculate \sqrt[3]{8} and get 2.

$$10-\frac{6}{2}+\sqrt[3]{-64}$$

Divide 6 by 2 to get 3.

$$10-3+\sqrt[3]{-64}$$

Subtract 3 from 10 to get 7.

$$7+\sqrt[3]{-64}$$

Calculate \sqrt[3]{-64} and get -4.

$$7-4$$

Subtract 4 from 7 to get 3.

$$3$$

Factor

$$3$$