Solve sqrt{1-3x}-1=0

$$\sqrt { 1 - 3 x } - 1 = 0$$

Solve for x

$$x=0$$

Steps for Solving Radical Equations

Add 1 to both sides of the equation.

$$\sqrt{-3x+1}-1-\left(-1\right)=-\left(-1\right)$$

Subtracting -1 from itself leaves 0.

$$\sqrt{-3x+1}=-\left(-1\right)$$

Subtract -1 from 0.

$$\sqrt{-3x+1}=1$$

Square both sides of the equation.

$$-3x+1=1$$

Subtract 1 from both sides of the equation.

$$-3x+1-1=1-1$$

Subtracting 1 from itself leaves 0.

$$-3x=1-1$$

Subtract 1 from 1.

$$-3x=0$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{0}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{0}{-3}$$

Divide 0 by -3.

$$x=0$$