Solve sqrt{1-0,6^2}+(0,4*0,2-2):0,2

$$\sqrt { 1 - 0,6 ^ { 2 } } + ( 0,4 \cdot 0,2 - 2 ) : 0,2$$

Evaluate

$$-8,6$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$\sqrt{1-0\times 36}+\frac{0,4\times 0,2-2}{0,2}$$

Multiply 0 and 36 to get 0.

$$\sqrt{1-0}+\frac{0,4\times 0,2-2}{0,2}$$

Subtract 0 from 1 to get 1.

$$\sqrt{1}+\frac{0,4\times 0,2-2}{0,2}$$

Calculate the square root of 1 and get 1.

$$1+\frac{0,4\times 0,2-2}{0,2}$$

Multiply 0,4 and 0,2 to get 0,08.

$$1+\frac{0,08-2}{0,2}$$

Subtract 2 from 0,08 to get -1,92.

$$1+\frac{-1,92}{0,2}$$

Expand \frac{-1,92}{0,2} by multiplying both numerator and the denominator by 100.

$$1+\frac{-192}{20}$$

Reduce the fraction \frac{-192}{20} to lowest terms by extracting and canceling out 4.

$$1-\frac{48}{5}$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{5}{5}-\frac{48}{5}$$

Since \frac{5}{5} and \frac{48}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-48}{5}$$

Subtract 48 from 5 to get -43.

$$-\frac{43}{5}$$

Factor

$$-8,6$$