Solve sqrt{1^2-4(1*2)}

$$\sqrt { 1 ^ { 2 } - 4 ( 1 \cdot 2 ) }$$

Evaluate (complex solution)

$$\sqrt{7}i\approx 2.645751311i$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$\sqrt{1-4\times 1\times 2}$$

Multiply 4 and 1 to get 4.

$$\sqrt{1-4\times 2}$$

Multiply 4 and 2 to get 8.

$$\sqrt{1-8}$$

Subtract 8 from 1 to get -7.

$$\sqrt{-7}$$

Factor -7=7\left(-1\right). Rewrite the square root of the product \sqrt{7\left(-1\right)} as the product of square roots \sqrt{7}\sqrt{-1}. By definition, the square root of -1 is i.

$$\sqrt{7}i$$

Evaluate

$$\text{Indeterminate}$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$\sqrt{1-4\times 1\times 2}$$

Multiply 4 and 1 to get 4.

$$\sqrt{1-4\times 2}$$

Multiply 4 and 2 to get 8.

$$\sqrt{1-8}$$

Subtract 8 from 1 to get -7.

$$\sqrt{-7}$$

Real Part (complex solution)

$$0$$