Solve sqrt{1^2+1^2+2^2}

$$\sqrt { 1 ^ { 2 } + 1 ^ { 2 } + 2 ^ { 2 } }$$

Evaluate

$$\sqrt{6}\approx 2.449489743$$

Solution Steps

Calculate 1 to the power of 2 and get 1.

$$\sqrt{1+1^{2}+2^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\sqrt{1+1+2^{2}}$$

Add 1 and 1 to get 2.

$$\sqrt{2+2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$\sqrt{2+4}$$

Add 2 and 4 to get 6.

$$\sqrt{6}$$