Solve sqrt{0.01}-sqrt[3]{8}+sqrt{6+1/4}

$$\sqrt { 0.01 } - \sqrt[ 3 ] { 8 } + \sqrt { 6 + \frac { 1 } { 4 } }$$

Evaluate

$$0.6$$

Solution Steps

Calculate the square root of 0.01 and get 0.1.

$$0.1-\sqrt[3]{8}+\sqrt{6+\frac{1}{4}}$$

Calculate \sqrt[3]{8} and get 2.

$$0.1-2+\sqrt{6+\frac{1}{4}}$$

Subtract 2 from 0.1 to get -1.9.

$$-1.9+\sqrt{6+\frac{1}{4}}$$

Add 6 and \frac{1}{4} to get \frac{25}{4}.

$$-1.9+\sqrt{\frac{25}{4}}$$

Rewrite the square root of the division \frac{25}{4} as the division of square roots \frac{\sqrt{25}}{\sqrt{4}}. Take the square root of both numerator and denominator.

$$-1.9+\frac{5}{2}$$

Add -1.9 and \frac{5}{2} to get \frac{3}{5}.

$$\frac{3}{5}$$

Factor

$$\frac{3}{5} = 0.6$$