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\left(\sqrt{-4x+17}\right)^{2}=\left(x+1\right)^{2}
Square both sides of the equation.
-4x+17=\left(x+1\right)^{2}
Calculate \sqrt{-4x+17} to the power of 2 and get -4x+17.
-4x+17=x^{2}+2x+1
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.
-4x+17-x^{2}=2x+1
Subtract x^{2} from both sides.
-4x+17-x^{2}-2x=1
Subtract 2x from both sides.
-6x+17-x^{2}=1
Combine -4x and -2x to get -6x.
-6x+17-x^{2}-1=0
Subtract 1 from both sides.
-6x+16-x^{2}=0
Subtract 1 from 17 to get 16.
-x^{2}-6x+16=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=-6 ab=-16=-16
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx+16. To find a and b, set up a system to be solved.
1,-16 2,-8 4,-4
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -16.
1-16=-15 2-8=-6 4-4=0
Calculate the sum for each pair.
a=2 b=-8
The solution is the pair that gives sum -6.
\left(-x^{2}+2x\right)+\left(-8x+16\right)
Rewrite -x^{2}-6x+16 as \left(-x^{2}+2x\right)+\left(-8x+16\right).
x\left(-x+2\right)+8\left(-x+2\right)
Factor out x in the first and 8 in the second group.
\left(-x+2\right)\left(x+8\right)
Factor out common term -x+2 by using distributive property.
x=2 x=-8
To find equation solutions, solve -x+2=0 and x+8=0.
\sqrt{-4\times 2+17}=2+1
Substitute 2 for x in the equation \sqrt{-4x+17}=x+1.
3=3
Simplify. The value x=2 satisfies the equation.
\sqrt{-4\left(-8\right)+17}=-8+1
Substitute -8 for x in the equation \sqrt{-4x+17}=x+1.
7=-7
Simplify. The value x=-8 does not satisfy the equation because the left and the right hand side have opposite signs.
x=2
Equation \sqrt{17-4x}=x+1 has a unique solution.