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\left(\sqrt{-3x-2}\right)^{2}=\left(x+2\right)^{2}
Square both sides of the equation.
-3x-2=\left(x+2\right)^{2}
Calculate \sqrt{-3x-2} to the power of 2 and get -3x-2.
-3x-2=x^{2}+4x+4
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.
-3x-2-x^{2}=4x+4
Subtract x^{2} from both sides.
-3x-2-x^{2}-4x=4
Subtract 4x from both sides.
-7x-2-x^{2}=4
Combine -3x and -4x to get -7x.
-7x-2-x^{2}-4=0
Subtract 4 from both sides.
-7x-6-x^{2}=0
Subtract 4 from -2 to get -6.
-x^{2}-7x-6=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=-7 ab=-\left(-6\right)=6
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx-6. To find a and b, set up a system to be solved.
-1,-6 -2,-3
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 6.
-1-6=-7 -2-3=-5
Calculate the sum for each pair.
a=-1 b=-6
The solution is the pair that gives sum -7.
\left(-x^{2}-x\right)+\left(-6x-6\right)
Rewrite -x^{2}-7x-6 as \left(-x^{2}-x\right)+\left(-6x-6\right).
x\left(-x-1\right)+6\left(-x-1\right)
Factor out x in the first and 6 in the second group.
\left(-x-1\right)\left(x+6\right)
Factor out common term -x-1 by using distributive property.
x=-1 x=-6
To find equation solutions, solve -x-1=0 and x+6=0.
\sqrt{-3\left(-1\right)-2}=-1+2
Substitute -1 for x in the equation \sqrt{-3x-2}=x+2.
1=1
Simplify. The value x=-1 satisfies the equation.
\sqrt{-3\left(-6\right)-2}=-6+2
Substitute -6 for x in the equation \sqrt{-3x-2}=x+2.
4=-4
Simplify. The value x=-6 does not satisfy the equation because the left and the right hand side have opposite signs.
x=-1
Equation \sqrt{-3x-2}=x+2 has a unique solution.