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Evaluate (complex solution)
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3i\sqrt{2}\sqrt{-10}
Factor -18=\left(3i\right)^{2}\times 2. Rewrite the square root of the product \sqrt{\left(3i\right)^{2}\times 2} as the product of square roots \sqrt{\left(3i\right)^{2}}\sqrt{2}. Take the square root of \left(3i\right)^{2}.
3i\sqrt{2}\sqrt{10}i
Factor -10=10\left(-1\right). Rewrite the square root of the product \sqrt{10\left(-1\right)} as the product of square roots \sqrt{10}\sqrt{-1}. By definition, the square root of -1 is i.
-3\sqrt{2}\sqrt{10}
Multiply 3i and i to get -3.
-3\sqrt{2}\sqrt{2}\sqrt{5}
Factor 10=2\times 5. Rewrite the square root of the product \sqrt{2\times 5} as the product of square roots \sqrt{2}\sqrt{5}.
-3\times 2\sqrt{5}
Multiply \sqrt{2} and \sqrt{2} to get 2.
-6\sqrt{5}
Multiply -3 and 2 to get -6.