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\sqrt{-12x+73}=1+3x
Subtract -3x from both sides of the equation.
\left(\sqrt{-12x+73}\right)^{2}=\left(1+3x\right)^{2}
Square both sides of the equation.
-12x+73=\left(1+3x\right)^{2}
Calculate \sqrt{-12x+73} to the power of 2 and get -12x+73.
-12x+73=1+6x+9x^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(1+3x\right)^{2}.
-12x+73-1=6x+9x^{2}
Subtract 1 from both sides.
-12x+72=6x+9x^{2}
Subtract 1 from 73 to get 72.
-12x+72-6x=9x^{2}
Subtract 6x from both sides.
-18x+72=9x^{2}
Combine -12x and -6x to get -18x.
-18x+72-9x^{2}=0
Subtract 9x^{2} from both sides.
-2x+8-x^{2}=0
Divide both sides by 9.
-x^{2}-2x+8=0
Rearrange the polynomial to put it in standard form. Place the terms in order from highest to lowest power.
a+b=-2 ab=-8=-8
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as -x^{2}+ax+bx+8. To find a and b, set up a system to be solved.
1,-8 2,-4
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -8.
1-8=-7 2-4=-2
Calculate the sum for each pair.
a=2 b=-4
The solution is the pair that gives sum -2.
\left(-x^{2}+2x\right)+\left(-4x+8\right)
Rewrite -x^{2}-2x+8 as \left(-x^{2}+2x\right)+\left(-4x+8\right).
x\left(-x+2\right)+4\left(-x+2\right)
Factor out x in the first and 4 in the second group.
\left(-x+2\right)\left(x+4\right)
Factor out common term -x+2 by using distributive property.
x=2 x=-4
To find equation solutions, solve -x+2=0 and x+4=0.
\sqrt{-12\times 2+73}-3\times 2=1
Substitute 2 for x in the equation \sqrt{-12x+73}-3x=1.
1=1
Simplify. The value x=2 satisfies the equation.
\sqrt{-12\left(-4\right)+73}-3\left(-4\right)=1
Substitute -4 for x in the equation \sqrt{-12x+73}-3x=1.
23=1
Simplify. The value x=-4 does not satisfy the equation.
x=2
Equation \sqrt{73-12x}=3x+1 has a unique solution.