Solve sqrt{-12-2a}=sqrt{-4-n}

$$\sqrt { - 12 - 2 a } = \sqrt { - 4 - n }$$

Solve for a

$$a=\frac{n-8}{2}$$

$$n\leq -4$$

Steps for Solving Radical Equations

Square both sides of the equation.

$$-2a-12=-n-4$$

Add 12 to both sides of the equation.

$$-2a-12-\left(-12\right)=-n-4-\left(-12\right)$$

Subtracting -12 from itself leaves 0.

$$-2a=-n-4-\left(-12\right)$$

Subtract -12 from -4-n.

$$-2a=8-n$$

Divide both sides by -2.

$$\frac{-2a}{-2}=\frac{8-n}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$a=\frac{8-n}{-2}$$

Divide 8-n by -2.

$$a=\frac{n}{2}-4$$

Solve for n

$$n=2\left(a+4\right)$$

$$a\leq -6$$