Solve sqrt{-1+25*2}+[12:(-2)*4]*4^2

$$\sqrt { - 1 + 25 \cdot 2 } + [ 12 : ( - 2 ) \cdot 4 ] \cdot 4 ^ { 2 }$$

Evaluate

$$-377$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\sqrt{-1+25\times 2}+\frac{12}{-2}\times 4^{3}$$

Multiply 25 and 2 to get 50.

$$\sqrt{-1+50}+\frac{12}{-2}\times 4^{3}$$

Add -1 and 50 to get 49.

$$\sqrt{49}+\frac{12}{-2}\times 4^{3}$$

Calculate the square root of 49 and get 7.

$$7+\frac{12}{-2}\times 4^{3}$$

Divide 12 by -2 to get -6.

$$7-6\times 4^{3}$$

Calculate 4 to the power of 3 and get 64.

$$7-6\times 64$$

Multiply -6 and 64 to get -384.

$$7-384$$

Subtract 384 from 7 to get -377.

$$-377$$

Factor

$$-377$$