Solve sqrt{-sqrt{144}:sqrt[3]{-27}}-[8-2*(4-3)]:2+[(-6)^2:(-2)^2]*3=

$$\sqrt { - \sqrt { 144 } : \sqrt[ 3 ] { - 27 } } - [ 8 - 2 \cdot ( 4 - 3 ) ] : 2 + [ ( - 6 ) ^ { 2 } : ( - 2 ) ^ { 2 } ] \cdot 3 =$$

Evaluate

$$26$$

Solution Steps

Calculate the square root of 144 and get 12.

$$\sqrt{\frac{-12}{\sqrt[3]{-27}}}-\frac{8-2\left(4-3\right)}{2}+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Calculate \sqrt[3]{-27} and get -3.

$$\sqrt{\frac{-12}{-3}}-\frac{8-2\left(4-3\right)}{2}+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Divide -12 by -3 to get 4.

$$\sqrt{4}-\frac{8-2\left(4-3\right)}{2}+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Calculate the square root of 4 and get 2.

$$2-\frac{8-2\left(4-3\right)}{2}+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Subtract 3 from 4 to get 1.

$$2-\frac{8-2\times 1}{2}+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Multiply 2 and 1 to get 2.

$$2-\frac{8-2}{2}+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Subtract 2 from 8 to get 6.

$$2-\frac{6}{2}+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Divide 6 by 2 to get 3.

$$2-3+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Subtract 3 from 2 to get -1.

$$-1+\frac{\left(-6\right)^{2}}{\left(-2\right)^{2}}\times 3$$

Calculate -6 to the power of 2 and get 36.

$$-1+\frac{36}{\left(-2\right)^{2}}\times 3$$

Calculate -2 to the power of 2 and get 4.

$$-1+\frac{36}{4}\times 3$$

Divide 36 by 4 to get 9.

$$-1+9\times 3$$

Multiply 9 and 3 to get 27.

$$-1+27$$

Add -1 and 27 to get 26.

$$26$$

Factor

$$2\times 13$$