Solve sqrt{(a-1-a+1)^2+(2a-1-2a+3^2)^2}

$$\sqrt { ( a - 1 - a + 1 ) ^ { 2 } + ( 2 a - 1 - 2 a + 3 ^ { 2 } ) ^ { 2 } }$$

Evaluate

$$8$$

Solution Steps

Combine a and -a to get 0.

$$\sqrt{\left(-1+1\right)^{2}+\left(2a-1-2a+3^{2}\right)^{2}}$$

Add -1 and 1 to get 0.

$$\sqrt{0^{2}+\left(2a-1-2a+3^{2}\right)^{2}}$$

Calculate 0 to the power of 2 and get 0.

$$\sqrt{0+\left(2a-1-2a+3^{2}\right)^{2}}$$

Combine 2a and -2a to get 0.

$$\sqrt{0+\left(-1+3^{2}\right)^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{0+\left(-1+9\right)^{2}}$$

Add -1 and 9 to get 8.

$$\sqrt{0+8^{2}}$$

Calculate 8 to the power of 2 and get 64.

$$\sqrt{0+64}$$

Add 0 and 64 to get 64.

$$\sqrt{64}$$

Calculate the square root of 64 and get 8.

$$8$$

Factor

$$2^{3}$$