Solve sqrt{(808-2)^2+(-1-3)^2}

$$\sqrt { ( 808 - 2 ) ^ { 2 } + ( - 1 - 3 ) ^ { 2 } }$$

Evaluate

$$2\sqrt{162413}\approx 806.009925497$$

Solution Steps

Subtract 2 from 808 to get 806.

$$\sqrt{806^{2}+\left(-1-3\right)^{2}}$$

Calculate 806 to the power of 2 and get 649636.

$$\sqrt{649636+\left(-1-3\right)^{2}}$$

Subtract 3 from -1 to get -4.

$$\sqrt{649636+\left(-4\right)^{2}}$$

Calculate -4 to the power of 2 and get 16.

$$\sqrt{649636+16}$$

Add 649636 and 16 to get 649652.

$$\sqrt{649652}$$

Factor 649652=2^{2}\times 162413. Rewrite the square root of the product \sqrt{2^{2}\times 162413} as the product of square roots \sqrt{2^{2}}\sqrt{162413}. Take the square root of 2^{2}.

$$2\sqrt{162413}$$