Solve sqrt{(8+2^2)*3+10-1^5}=

$$\sqrt { ( 8 + 2 ^ { 2 } ) \cdot 3 + 10 - 1 ^ { 5 } } =$$

Evaluate

$$3\sqrt{5}\approx 6.708203932$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{\left(8+4\right)\times 3+10-1^{5}}$$

Add 8 and 4 to get 12.

$$\sqrt{12\times 3+10-1^{5}}$$

Multiply 12 and 3 to get 36.

$$\sqrt{36+10-1^{5}}$$

Add 36 and 10 to get 46.

$$\sqrt{46-1^{5}}$$

Calculate 1 to the power of 5 and get 1.

$$\sqrt{46-1}$$

Subtract 1 from 46 to get 45.

$$\sqrt{45}$$

Factor 45=3^{2}\times 5. Rewrite the square root of the product \sqrt{3^{2}\times 5} as the product of square roots \sqrt{3^{2}}\sqrt{5}. Take the square root of 3^{2}.

$$3\sqrt{5}$$