Solve sqrt{(6-5*5)^2+(6-6)^2}

$$\sqrt { ( 6 - 5 \cdot 5 ) ^ { 2 } + ( 6 - 6 ) ^ { 2 } }$$

Evaluate

$$19$$

Solution Steps

Multiply 5 and 5 to get 25.

$$\sqrt{\left(6-25\right)^{2}+\left(6-6\right)^{2}}$$

Subtract 25 from 6 to get -19.

$$\sqrt{\left(-19\right)^{2}+\left(6-6\right)^{2}}$$

Calculate -19 to the power of 2 and get 361.

$$\sqrt{361+\left(6-6\right)^{2}}$$

Subtract 6 from 6 to get 0.

$$\sqrt{361+0^{2}}$$

Calculate 0 to the power of 2 and get 0.

$$\sqrt{361+0}$$

Add 361 and 0 to get 361.

$$\sqrt{361}$$

Calculate the square root of 361 and get 19.

$$19$$

Factor

$$19$$