Solve sqrt{(4-7)^2+(6-8)^2}

$$\sqrt { ( 4 - 7 ) ^ { 2 } + ( 6 - 8 ) ^ { 2 } }$$

Evaluate

$$\sqrt{13}\approx 3.605551275$$

Solution Steps

Subtract 7 from 4 to get -3.

$$\sqrt{\left(-3\right)^{2}+\left(6-8\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$\sqrt{9+\left(6-8\right)^{2}}$$

Subtract 8 from 6 to get -2.

$$\sqrt{9+\left(-2\right)^{2}}$$

Calculate -2 to the power of 2 and get 4.

$$\sqrt{9+4}$$

Add 9 and 4 to get 13.

$$\sqrt{13}$$