Solve sqrt{(4-2*5)^2+(4-3)^2}

$$\sqrt { ( 4 - 2 \cdot 5 ) ^ { 2 } + ( 4 - 3 ) ^ { 2 } }$$

Evaluate

$$\sqrt{37}\approx 6.08276253$$

Solution Steps

Multiply 2 and 5 to get 10.

$$\sqrt{\left(4-10\right)^{2}+\left(4-3\right)^{2}}$$

Subtract 10 from 4 to get -6.

$$\sqrt{\left(-6\right)^{2}+\left(4-3\right)^{2}}$$

Calculate -6 to the power of 2 and get 36.

$$\sqrt{36+\left(4-3\right)^{2}}$$

Subtract 3 from 4 to get 1.

$$\sqrt{36+1^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$\sqrt{36+1}$$

Add 36 and 1 to get 37.

$$\sqrt{37}$$