Solve sqrt{(3^2-5^2)+(8+5*2-3*5)^2}

$$\sqrt { ( 3 ^ { 2 } - 5 ^ { 2 } ) + ( 8 + 5 \times 2 - 3 \times 5 ) ^ { 2 } }$$

Evaluate

$$\text{Indeterminate}$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$\sqrt{9-5^{2}+\left(8+5\times 2-3\times 5\right)^{2}}$$

Calculate 5 to the power of 2 and get 25.

$$\sqrt{9-25+\left(8+5\times 2-3\times 5\right)^{2}}$$

Subtract 25 from 9 to get -16.

$$\sqrt{-16+\left(8+5\times 2-3\times 5\right)^{2}}$$

Multiply 5 and 2 to get 10.

$$\sqrt{-16+\left(8+10-3\times 5\right)^{2}}$$

Add 8 and 10 to get 18.

$$\sqrt{-16+\left(18-3\times 5\right)^{2}}$$

Multiply 3 and 5 to get 15.

$$\sqrt{-16+\left(18-15\right)^{2}}$$

Subtract 15 from 18 to get 3.

$$\sqrt{-16+3^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{-16+9}$$

Add -16 and 9 to get -7.

$$\sqrt{-7}$$