Solve sqrt{(11*32)+7^2-1}+4^2*10+3^2=

$$\sqrt { ( 11 \times 32 ) + 7 ^ { 2 } - 1 } + 4 ^ { 2 } \times 10 + 3 ^ { 2 } =$$

Evaluate

$$189$$

Solution Steps

Multiply 11 and 32 to get 352.

$$\sqrt{352+7^{2}-1}+4^{2}\times 10+3^{2}$$

Calculate 7 to the power of 2 and get 49.

$$\sqrt{352+49-1}+4^{2}\times 10+3^{2}$$

Add 352 and 49 to get 401.

$$\sqrt{401-1}+4^{2}\times 10+3^{2}$$

Subtract 1 from 401 to get 400.

$$\sqrt{400}+4^{2}\times 10+3^{2}$$

Calculate the square root of 400 and get 20.

$$20+4^{2}\times 10+3^{2}$$

Calculate 4 to the power of 2 and get 16.

$$20+16\times 10+3^{2}$$

Multiply 16 and 10 to get 160.

$$20+160+3^{2}$$

Add 20 and 160 to get 180.

$$180+3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$180+9$$

Add 180 and 9 to get 189.

$$189$$

Factor

$$3^{3}\times 7$$