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\sqrt{1+\left(\sqrt{3}\right)^{2}}=x
Calculate 1 to the power of 2 and get 1.
\sqrt{1+3}=x
The square of \sqrt{3} is 3.
\sqrt{4}=x
Add 1 and 3 to get 4.
2=x
Calculate the square root of 4 and get 2.
x=2
Swap sides so that all variable terms are on the left hand side.