Solve sqrt{(-8-19)}*(-5+2)^2-37+[4div2+3*(-3)-3]

$$\sqrt { ( - 8 - 19 ) } \times ( - 5 + 2 ) ^ { 2 } - 37 + [ 4 \div 2 + 3 \cdot ( - 3 ) - 3 ]$$

Evaluate (complex solution)

$$-47+27\sqrt{3}i\approx -47+46.765371804i$$

Solution Steps

Subtract 19 from -8 to get -27.

$$\sqrt{-27}\left(-5+2\right)^{2}-37+\frac{4}{2}+3\left(-3\right)-3$$

Factor -27=\left(3i\right)^{2}\times 3. Rewrite the square root of the product \sqrt{\left(3i\right)^{2}\times 3} as the product of square roots \sqrt{\left(3i\right)^{2}}\sqrt{3}. Take the square root of \left(3i\right)^{2}.

$$3i\sqrt{3}\left(-5+2\right)^{2}-37+\frac{4}{2}+3\left(-3\right)-3$$

Add -5 and 2 to get -3.

$$3i\sqrt{3}\left(-3\right)^{2}-37+\frac{4}{2}+3\left(-3\right)-3$$

Calculate -3 to the power of 2 and get 9.

$$3i\sqrt{3}\times 9-37+\frac{4}{2}+3\left(-3\right)-3$$

Multiply 3i and 9 to get 27i.

$$27i\sqrt{3}-37+\frac{4}{2}+3\left(-3\right)-3$$

Divide 4 by 2 to get 2.

$$27i\sqrt{3}-37+2+3\left(-3\right)-3$$

Add -37 and 2 to get -35.

$$27i\sqrt{3}-35+3\left(-3\right)-3$$

Multiply 3 and -3 to get -9.

$$27i\sqrt{3}-35-9-3$$

Subtract 9 from -35 to get -44.

$$27i\sqrt{3}-44-3$$

Subtract 3 from -44 to get -47.

$$27i\sqrt{3}-47$$

Real Part (complex solution)

$$-47$$

Evaluate

$$\text{Indeterminate}$$