Solve sqrt{(-5)^2}+sqrt{(-3/5)^2}=

$$\sqrt { ( - 5 ) ^ { 2 } } + \sqrt { ( - \frac { 3 } { 5 } ) ^ { 2 } } =$$

Evaluate

$$\frac{28}{5}=5.6$$

Solution Steps

Calculate -5 to the power of 2 and get 25.

$$\sqrt{25}+\sqrt{\left(-\frac{3}{5}\right)^{2}}$$

Calculate the square root of 25 and get 5.

$$5+\sqrt{\left(-\frac{3}{5}\right)^{2}}$$

Calculate -\frac{3}{5} to the power of 2 and get \frac{9}{25}.

$$5+\sqrt{\frac{9}{25}}$$

Rewrite the square root of the division \frac{9}{25} as the division of square roots \frac{\sqrt{9}}{\sqrt{25}}. Take the square root of both numerator and denominator.

$$5+\frac{3}{5}$$

Convert 5 to fraction \frac{25}{5}.

$$\frac{25}{5}+\frac{3}{5}$$

Since \frac{25}{5} and \frac{3}{5} have the same denominator, add them by adding their numerators.

$$\frac{25+3}{5}$$

Add 25 and 3 to get 28.

$$\frac{28}{5}$$

Factor

$$\frac{2 ^ {2} \cdot 7}{5} = 5\frac{3}{5} = 5.6$$