Solve sqrt{(-3)^2}-sqrt{64}divsqrt[3]{-8}+sqrt[3]{27}

$$\sqrt { ( - 3 ) ^ { 2 } } - \sqrt { 64 } \div \sqrt[ 3 ] { - 8 } + \sqrt[ 3 ] { 27 }$$

Evaluate

$$10$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$\sqrt{9}-\frac{\sqrt{64}}{\sqrt[3]{-8}}+\sqrt[3]{27}$$

Calculate the square root of 9 and get 3.

$$3-\frac{\sqrt{64}}{\sqrt[3]{-8}}+\sqrt[3]{27}$$

Calculate the square root of 64 and get 8.

$$3-\frac{8}{\sqrt[3]{-8}}+\sqrt[3]{27}$$

Calculate \sqrt[3]{-8} and get -2.

$$3-\frac{8}{-2}+\sqrt[3]{27}$$

Divide 8 by -2 to get -4.

$$3-\left(-4\right)+\sqrt[3]{27}$$

The opposite of -4 is 4.

$$3+4+\sqrt[3]{27}$$

Add 3 and 4 to get 7.

$$7+\sqrt[3]{27}$$

Calculate \sqrt[3]{27} and get 3.

$$7+3$$

Add 7 and 3 to get 10.

$$10$$

Factor

$$2\times 5$$