Solve sqrt{(-3)^2}+(-1)^6-(-1,2)^0+sqrt[3]{4^6}

$$\sqrt { ( - 3 ) ^ { 2 } } + ( - 1 ) ^ { 6 } - ( - 1,2 ) ^ { 0 } + \sqrt[ 3 ] { 4 ^ { 6 } }$$

Evaluate

$$19$$

Solution Steps

Calculate -3 to the power of 2 and get 9.

$$\sqrt{9}+\left(-1\right)^{6}-\left(-1,2\right)^{0}+\sqrt[3]{4^{6}}$$

Calculate the square root of 9 and get 3.

$$3+\left(-1\right)^{6}-\left(-1,2\right)^{0}+\sqrt[3]{4^{6}}$$

Calculate -1 to the power of 6 and get 1.

$$3+1-\left(-1,2\right)^{0}+\sqrt[3]{4^{6}}$$

Add 3 and 1 to get 4.

$$4-\left(-1,2\right)^{0}+\sqrt[3]{4^{6}}$$

Calculate -1,2 to the power of 0 and get 1.

$$4-1+\sqrt[3]{4^{6}}$$

Subtract 1 from 4 to get 3.

$$3+\sqrt[3]{4^{6}}$$

Calculate 4 to the power of 6 and get 4096.

$$3+\sqrt[3]{4096}$$

Calculate \sqrt[3]{4096} and get 16.

$$3+16$$

Add 3 and 16 to get 19.

$$19$$

Factor

$$19$$