Solve sqrt{(-2)^2}-1+1/9*(-3)^2+sqrt[3]{-8}

$$\sqrt { ( - 2 ) ^ { 2 } } - 1 + \frac { 1 } { 9 } \times ( - 3 ) ^ { 2 } + \sqrt[ 3 ] { - 8 }$$

Evaluate

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Solution Steps

Calculate -2 to the power of 2 and get 4.

$$\sqrt{4}-1+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Calculate the square root of 4 and get 2.

$$2-1+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Subtract 1 from 2 to get 1.

$$1+\frac{1}{9}\left(-3\right)^{2}+\sqrt[3]{-8}$$

Calculate -3 to the power of 2 and get 9.

$$1+\frac{1}{9}\times 9+\sqrt[3]{-8}$$

Multiply \frac{1}{9} and 9 to get 1.

$$1+1+\sqrt[3]{-8}$$

Add 1 and 1 to get 2.

$$2+\sqrt[3]{-8}$$

Calculate \sqrt[3]{-8} and get -2.

$$2-2$$

Subtract 2 from 2 to get 0.

$$0$$

Factor

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