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\sqrt{4}+\left(-2\sqrt{3}\right)^{2}-\sqrt{7}\left(3\sqrt{28}-\frac{\sqrt{4}}{\sqrt{7}}\right)
Calculate -2 to the power of 2 and get 4.
2+\left(-2\sqrt{3}\right)^{2}-\sqrt{7}\left(3\sqrt{28}-\frac{\sqrt{4}}{\sqrt{7}}\right)
Calculate the square root of 4 and get 2.
2+\left(-2\right)^{2}\left(\sqrt{3}\right)^{2}-\sqrt{7}\left(3\sqrt{28}-\frac{\sqrt{4}}{\sqrt{7}}\right)
Expand \left(-2\sqrt{3}\right)^{2}.
2+4\left(\sqrt{3}\right)^{2}-\sqrt{7}\left(3\sqrt{28}-\frac{\sqrt{4}}{\sqrt{7}}\right)
Calculate -2 to the power of 2 and get 4.
2+4\times 3-\sqrt{7}\left(3\sqrt{28}-\frac{\sqrt{4}}{\sqrt{7}}\right)
The square of \sqrt{3} is 3.
2+12-\sqrt{7}\left(3\sqrt{28}-\frac{\sqrt{4}}{\sqrt{7}}\right)
Multiply 4 and 3 to get 12.
14-\sqrt{7}\left(3\sqrt{28}-\frac{\sqrt{4}}{\sqrt{7}}\right)
Add 2 and 12 to get 14.
14-\sqrt{7}\left(3\times 2\sqrt{7}-\frac{\sqrt{4}}{\sqrt{7}}\right)
Factor 28=2^{2}\times 7. Rewrite the square root of the product \sqrt{2^{2}\times 7} as the product of square roots \sqrt{2^{2}}\sqrt{7}. Take the square root of 2^{2}.
14-\sqrt{7}\left(6\sqrt{7}-\frac{\sqrt{4}}{\sqrt{7}}\right)
Multiply 3 and 2 to get 6.
14-\sqrt{7}\left(6\sqrt{7}-\frac{2}{\sqrt{7}}\right)
Calculate the square root of 4 and get 2.
14-\sqrt{7}\left(6\sqrt{7}-\frac{2\sqrt{7}}{\left(\sqrt{7}\right)^{2}}\right)
Rationalize the denominator of \frac{2}{\sqrt{7}} by multiplying numerator and denominator by \sqrt{7}.
14-\sqrt{7}\left(6\sqrt{7}-\frac{2\sqrt{7}}{7}\right)
The square of \sqrt{7} is 7.
14-\sqrt{7}\times \frac{40}{7}\sqrt{7}
Combine 6\sqrt{7} and -\frac{2\sqrt{7}}{7} to get \frac{40}{7}\sqrt{7}.
14-7\times \frac{40}{7}
Multiply \sqrt{7} and \sqrt{7} to get 7.
14-40
Multiply 7 and \frac{40}{7} to get 40.
-26
Subtract 40 from 14 to get -26.