Solve sqrt{(-2)^2}+|-1/25|+sqrt[3]{-8}-(-5)^-2=

$$\sqrt { ( - 2 ) ^ { 2 } } + | - \frac { 1 } { 25 } | + \sqrt[ 3 ] { - 8 } - ( - 5 ) ^ { - 2 } =$$

Evaluate

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Solution Steps

Calculate -2 to the power of 2 and get 4.

$$\sqrt{4}+|-\frac{1}{25}|+\sqrt[3]{-8}-\left(-5\right)^{-2}$$

Calculate the square root of 4 and get 2.

$$2+|-\frac{1}{25}|+\sqrt[3]{-8}-\left(-5\right)^{-2}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -\frac{1}{25} is \frac{1}{25}.

$$2+\frac{1}{25}+\sqrt[3]{-8}-\left(-5\right)^{-2}$$

Add 2 and \frac{1}{25} to get \frac{51}{25}.

$$\frac{51}{25}+\sqrt[3]{-8}-\left(-5\right)^{-2}$$

Calculate \sqrt[3]{-8} and get -2.

$$\frac{51}{25}-2-\left(-5\right)^{-2}$$

Subtract 2 from \frac{51}{25} to get \frac{1}{25}.

$$\frac{1}{25}-\left(-5\right)^{-2}$$

Calculate -5 to the power of -2 and get \frac{1}{25}.

$$\frac{1}{25}-\frac{1}{25}$$

Subtract \frac{1}{25} from \frac{1}{25} to get 0.

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Factor

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