Solve for a
a=\left(e^{2}+2\right)z
z\neq 0
Solve for z
z=\frac{a}{e^{2}+2}
a\neq 0
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\frac{1}{z}a-2=e^{2}
Square both sides of the equation.
\frac{1}{z}a-2-\left(-2\right)=e^{2}-\left(-2\right)
Add 2 to both sides of the equation.
\frac{1}{z}a=e^{2}-\left(-2\right)
Subtracting -2 from itself leaves 0.
\frac{1}{z}a=e^{2}+2
Subtract -2 from e^{2}.
\frac{\frac{1}{z}az}{1}=\frac{\left(e^{2}+2\right)z}{1}
Divide both sides by z^{-1}.
a=\frac{\left(e^{2}+2\right)z}{1}
Dividing by z^{-1} undoes the multiplication by z^{-1}.
a=\left(e^{2}+2\right)z
Divide e^{2}+2 by z^{-1}.
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