Solve sqrt{9/4*(1-1/2)^2}

$$\sqrt { \frac { 9 } { 4 } \cdot ( 1 - \frac { 1 } { 2 } ) ^ { 2 } }$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Subtract \frac{1}{2} from 1 to get \frac{1}{2}.

$$\sqrt{\frac{9}{4}\times \left(\frac{1}{2}\right)^{2}}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\sqrt{\frac{9}{4}\times \frac{1}{4}}$$

Multiply \frac{9}{4} and \frac{1}{4} to get \frac{9}{16}.

$$\sqrt{\frac{9}{16}}$$

Rewrite the square root of the division \frac{9}{16} as the division of square roots \frac{\sqrt{9}}{\sqrt{16}}. Take the square root of both numerator and denominator.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$