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\frac{\sqrt{9}}{\sqrt{2}}+\frac{1}{2}
Rewrite the square root of the division \sqrt{\frac{9}{2}} as the division of square roots \frac{\sqrt{9}}{\sqrt{2}}.
\frac{3}{\sqrt{2}}+\frac{1}{2}
Calculate the square root of 9 and get 3.
\frac{3\sqrt{2}}{\left(\sqrt{2}\right)^{2}}+\frac{1}{2}
Rationalize the denominator of \frac{3}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
\frac{3\sqrt{2}}{2}+\frac{1}{2}
The square of \sqrt{2} is 2.
\frac{3\sqrt{2}+1}{2}
Since \frac{3\sqrt{2}}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.