Verify
true
Share
Copied to clipboard
\frac{\sqrt{5}}{\sqrt{9}}=\frac{1}{3}\sqrt{5}
Rewrite the square root of the division \sqrt{\frac{5}{9}} as the division of square roots \frac{\sqrt{5}}{\sqrt{9}}.
\frac{\sqrt{5}}{3}=\frac{1}{3}\sqrt{5}
Calculate the square root of 9 and get 3.
\frac{\sqrt{5}}{3}-\frac{1}{3}\sqrt{5}=0
Subtract \frac{1}{3}\sqrt{5} from both sides.
0=0
Combine \frac{\sqrt{5}}{3} and -\frac{1}{3}\sqrt{5} to get 0.
\text{true}
Compare 0 and 0.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}