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\frac{\sqrt{2}}{\sqrt{3}}\times \frac{6}{4}-\frac{10}{4}
Rewrite the square root of the division \sqrt{\frac{2}{3}} as the division of square roots \frac{\sqrt{2}}{\sqrt{3}}.
\frac{\sqrt{2}\sqrt{3}}{\left(\sqrt{3}\right)^{2}}\times \frac{6}{4}-\frac{10}{4}
Rationalize the denominator of \frac{\sqrt{2}}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\sqrt{2}\sqrt{3}}{3}\times \frac{6}{4}-\frac{10}{4}
The square of \sqrt{3} is 3.
\frac{\sqrt{6}}{3}\times \frac{6}{4}-\frac{10}{4}
To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.
\frac{\sqrt{6}}{3}\times \frac{3}{2}-\frac{10}{4}
Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.
\frac{\sqrt{6}\times 3}{3\times 2}-\frac{10}{4}
Multiply \frac{\sqrt{6}}{3} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
\frac{\sqrt{6}}{2}-\frac{10}{4}
Cancel out 3 in both numerator and denominator.
\frac{\sqrt{6}}{2}-\frac{5}{2}
Reduce the fraction \frac{10}{4} to lowest terms by extracting and canceling out 2.
\frac{\sqrt{6}-5}{2}
Since \frac{\sqrt{6}}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.