Solve sqrt{2^2/1*[5^2/4*4^2/1]}

$$\sqrt { \frac { 2 ^ { 2 } } { 1 } \cdot [ \frac { 5 ^ { 2 } } { 4 } \cdot \frac { 4 ^ { 2 } } { 1 } ] }$$

Evaluate

$$20$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{\frac{4}{1}\times \frac{5^{2}}{4}\times \frac{4^{2}}{1}}$$

Anything divided by one gives itself.

$$\sqrt{4\times \frac{5^{2}}{4}\times \frac{4^{2}}{1}}$$

Calculate 5 to the power of 2 and get 25.

$$\sqrt{4\times \frac{25}{4}\times \frac{4^{2}}{1}}$$

Cancel out 4 and 4.

$$\sqrt{25\times \frac{4^{2}}{1}}$$

Calculate 4 to the power of 2 and get 16.

$$\sqrt{25\times \frac{16}{1}}$$

Anything divided by one gives itself.

$$\sqrt{25\times 16}$$

Multiply 25 and 16 to get 400.

$$\sqrt{400}$$

Calculate the square root of 400 and get 20.

$$20$$

Factor

$$2^{2}\times 5$$